When 40 g of aluminum oxide interacted with sulfuric acid, a salt was formed. Determine the mass of salt.

univerkov | September 1, 2021 | education

Let’s find the amount of substance Al2O3.

n = m: M.

M (Al2O3) = 102 g / mol.

n = 40 g: 102 g / mol = 0.39 mol.

Let’s find the quantitative ratios of substances.

Al2O3 + 3H2SO4 = Al2 (SO4) 3 + 3H2O.

For 1 mol of Al2O3, there is 1 mol of Al2 (SO4) 3.

Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (Al2O3) = n (Al2 (SO4) 3) = 0.39 mol.

Find the mass of Al2 (SO4) 3.

M (Al2 (SO4) 3) = 342 g / mol.

m = n × M.

m = 342 g / mol × 0.39 mol = 133.38 g.

Answer: 133.38 g.

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