When 40 g of calcium carbonate is dissolved in an excess of hydrochloric acid, … l of carbon dioxide is formed.

univerkov | July 9, 2021 | education

Reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O

The amount of CaCO3 substance:

v (CaCO3) = m (CaCO3) / M (CaCO3) = 40/100 = 0.4 (mol).

According to the reaction equation, 1 mol of CaCO3 forms 1 mol of CO2, therefore

v (CaCO3) = v (CO2) = 0.4 (mol).

Then the volume of carbon dioxide released during normal operation. (under normal conditions):

V (CO2) = v (CO2) * Vm = 0.4 * 22.4 = 8.96 (L).

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