When 40 grams of methane is burned, carbon dioxide is formed. Find its volume.

Let us write the equation for the reaction of methane combustion:

CH4 + 2O2 = CO2 + 2H2O

Let’s find the amount of methane substance:

v (CH4) = m (CH4) / M (CH4) = 40/16 = 2.5 (mol).

According to the reaction equation, 1 mol of CO2 is formed per 1 mol of CH4, therefore:

v (CO2) = v (CH4) = 2.5 (mol).

Thus, the volume of emitted carbon dioxide, measured under normal conditions (n.o.):

V (CO2) = v (CO2) * Vm = 2.5 * 22.4 = 56 (l).

Answer: 56 l.