Let us write the equation for the reaction of methane combustion:
CH4 + 2O2 = CO2 + 2H2O
Let’s find the amount of methane substance:
v (CH4) = m (CH4) / M (CH4) = 40/16 = 2.5 (mol).
According to the reaction equation, 1 mol of CO2 is formed per 1 mol of CH4, therefore:
v (CO2) = v (CH4) = 2.5 (mol).
Thus, the volume of emitted carbon dioxide, measured under normal conditions (n.o.):
V (CO2) = v (CO2) * Vm = 2.5 * 22.4 = 56 (l).
Answer: 56 l.
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