When 400 g of 10% KOH solution interacted with formic acid, a salt was formed.

When 400 g of 10% KOH solution interacted with formic acid, a salt was formed. Determine the mass and quantity of salt, if the yield is 95%.

Reaction of potassium hydroxide with formic acid.

KOH + HCOOH = HCOOK + H2O.

Let’s calculate the mass of a substance in an alkali solution.

m (KOH) = W (KOH) • m (solution) / 100% = 10 • 400/100 = 40 g.

Number of moles:

n (KOH) = m / Mr = 40/56 = 0.7 mol.

The number of moles of the salt obtained will be equal to the number of moles of potassium hydroxide.

Let us find the theoretical yield of potassium formate:

m (NSOOK) = n • Mr = 0.7 • 84 = 58.8 g.

Practical way out:

m (NSOOK) = m (NSOOK) theor • W (pr.) / W (theor.) = 58.8 • 95/100 = 55.9 g.