When 48 g of magnesium reacted with hydrochloric acid, hydrogen was formed.

When 48 g of magnesium reacted with hydrochloric acid, hydrogen was formed. Determine the mass of hydrogen at 80% yield.

Magnesium interacts with hydrochloric acid. This produces hydrogen gas.

Mg + 2HCl = MgCl2 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 48/24 = 2 mol;

Taking into account the yield of 80%, the amount of synthesized hydrogen will be 2 x 0.8 = 1.6 mol.

Let’s calculate its weight, for this we multiply the amount of substance by the weight of 1 mole of gas:

M H2 = 2 grams / mol;

m H2 = 2 x 1.6 = 3.2 grams;