When 5.75 g of alkali metal was dissolved in water, 2.8 liters of hydrogen were released. Identify the metal.

univerkov | December 3, 2020 | education

2Me + 2H2O = 2MeOH + H2
n (H2) = V \ Vm = 2.8 \ 22.4 = 0.125 mol
for ur-th p-i n (Me) = 0.125 * 2 = 0.25 mol
M (Me) = m \ n = 5.75 \ 0.25 = 23 g mol
Me = Na (sodium)
Answer: Na

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