When 5 grams of aluminum is burned, 9.44 g of aluminum oxide is formed. Determine the equivalent weight of aluminum.

m (Al) = 5 g.
m (Al2O3) = 9.44 g.
Let us determine the equivalent mass of aluminum. We write down the solution.
We write down the equation of reactions.
4Al + 3O2 = 2Al2O3
ne (Al2O3) = ne (Al)
The amount of alumina equivalent material is equal to the amount of aluminum equivalent material.
m1 / Me1 = m2 / Me2.
Where m is the mass of the substance.
M is the molar mass of the substance.
Find the molar mass of the aluminum oxide equivalent.
Me (Al2O3) = 102/3 * 2 = 17 g / mol eq.
Find the molar mass of the aluminum equivalent.
Me2 = m2 * Me1 / m1 = 5 * 17 / 9.44 = 9,0004 g / mol eq.
Answer: Me (Al) = 9,0004 g / mol eq.