When 6.72 liters of carbon dioxide was passed through a solution of barium hydroxide with a mass fraction of 41%

When 6.72 liters of carbon dioxide was passed through a solution of barium hydroxide with a mass fraction of 41%, barium carbonate was formed. Calculate the mass of the barium hydroxide stock solution.

Ba (OH) 2 + CO2 = BaCO3 + H2O
n (CO2) = V \ Vm = 6.72 \ 22.4 = 0.3 mol
by ur-y p-i n (Ba (OH) 2) = n (CO2) = 0.3 mol
m (Ba (OH) 2) = n * M = 0.3 * 171 = 51.3 g
m (solution Ba (OH) 2) = m (in-va) \ w = 51.3 \ 0.41 = 125 g
Answer: 125 g