When 62 g of phosphorus is burned in oxygen, phosphorus oxide (V) was obtained.

When 62 g of phosphorus is burned in oxygen, phosphorus oxide (V) was obtained. Find the volume of oxygen 4P + 5O2 = 2P2O5

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In this case, 2 molecules of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in phosphorus weighing 62 grams.

M P = 31 grams / mol;

N P = 62/31 = 2 mol;

To burn this amount of phosphorus, 2 x 5/4 = 2.5 mol of oxygen will be required.

Let’s calculate its volume.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

The required volume of oxygen will be:

V O2 = 2.5 x 22.4 = 56 liters;