When 7 grams of Zn interacted with H2SO4, 2.24 liters of hydrogen were released. determine the W impurities in Zn.

1. Let’s write the equation of the reaction of zinc with sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 ↑;

2. find the chemical amount of hydrogen:

n (H2) = V (H2): Vm = 2.24: 22.4 = 0.1 mol;

3. Determine the chemical amount of zinc:

n (Zn) = n (H2) = 0.1 mol;

4.calculated the mass of pure zinc:

m (Zn) = n (Zn) * M (Zn) = 0.1 * 65 = 6.5 g;

5.Calculate the mass of impurities:

m (impurities) = m (sample) – m (Zn) = 7 – 6.5 = 0.5 mol;

6.determine the mass fraction of impurities:

w (impurities) = m (impurities): m (sample) = 0.5: 7 = 0.0714 or 7.14%.

Answer: 7.14%.