When a 0.6 C charge moves from one end of the conductor to the other, the electric field does the work of 6 J.

When a 0.6 C charge moves from one end of the conductor to the other, the electric field does the work of 6 J. Determine the electric voltage at the ends of the conductor.

Decision:
U = A / q = 6 / 0.6 = 10 V
Answer: 10V



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