When a 32 g sulfuric acid solution interacted with an excess of barium

When a 32 g sulfuric acid solution interacted with an excess of barium chloride solution, a 10 g precipitate was formed. Determine the mass fraction of sulfuric acid in the original solution.

Barium chloride salt reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equivalent molar amounts. In this case, the same amount of insoluble salt is synthesized.

Let’s calculate the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

N BaSO4 = 10/233 = 0.043 mol;

Let’s calculate the weight of the same amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.043 x 98 = 4.214 grams;

The acid concentration will be 4.214 / 32 = 0.1317 = 13.17%;