When a box weighing 120 kg was evenly pulled on the floor, we did a work equal to 8400 kJ, how far did it move?

Initial data: the movement of the box is uniform; m (box weight) = 120 kg; A (work done while moving the box) = 8400 J; we assume that the box and the floor are made of wood.

Reference values: μ (wood-to-wood friction coefficient) = 0.5.

We express the distance by which the box was moved from the formula: A = F * S = Ftr. * S = μ * m * g * S, whence S = A / (μ * m * g).

Calculation: S = 8400 / (0.5 * 120 * 10) = 14 m.

Answer: The box was moved 14 m.