When a conductor with a diameter of 0.5 mm and a length of 4.5 m was included in the electrical circuit

| August 19, 2021 | education

When a conductor with a diameter of 0.5 mm and a length of 4.5 m was included in the electrical circuit, the potential difference at its ends turned out to be 1.2 V at a current of 1.0 A. What is the specific resistance of the conductor material?

Data: d (diameter of the conductor included in the circuit) = 0.5 mm; l (conductor length) = 4.5 m; φ1 – φ2 (potential difference) = 1.2 V; I (current) = 1 A.

1) Determine the resistance of the connected conductor: R = (φ1 – φ2) / I = 1.2 / 1 = 1.2 Ohm.

2) Calculate the cross-sectional area: S = Π * d ^ 2/2 = 3.14 * 0.5 ^ 2/4 = 0.19625 mm2.

3) Calculate beats. electrical resistance: ρ = R * S / l = 1.2 * 0.19625 / 4.5 = 0.0523 Ohm * mm2 / m.

Answer: The specific electrical resistance is 0.0523 Ohm * mm2 / m.



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