When a cyclist moves around a circle with a radius of 40 m with a constant modulus of 10 m / s

When a cyclist moves around a circle with a radius of 40 m with a constant modulus of 10 m / s, the acceleration of his movement is equal to …

Given: R (radius of the circle along which the cyclist under consideration moves) = 40 m; V (constant cyclist speed) = 10 m / s.

The acceleration of the cyclist under consideration when moving in a circle is determined by the formula: a = √ (an ^ 2 + aτ ^ 2) = √ ((V ^ 2 / R) ^ 2 + 0 ^ 2) = V2 / R.

Let’s perform the calculation: a = 10 ^ 2/40 = 2.5 m / s2.

Answer: 3) the acceleration of the cyclist in question is 2.5 m / s2.