When a piece of aluminum is completely immersed in kerosene, a buoyant force F = 120H acts on it.

When a piece of aluminum is completely immersed in kerosene, a buoyant force F = 120H acts on it. Determine the volume of the piece of aluminum.

Initial data: Fa (buoyancy force that acts on a piece of aluminum) = 120 N; a piece of aluminum is completely immersed in kerosene.

Reference values: ρк (kerosene density) = 800 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

We express the volume of a piece of aluminum from the formula for calculating the Archimedes force: Fa = ρк * g * V, whence V = Fa / (ρк * g).

Calculation: V = 120 / (800 * 10) = 0.015 m3 (15 dm3).

Answer: The volume of a piece of aluminum is 15 dm3.