When a piece of metal weighing 200 g was heated from 20 to 60 degrees, its internal energy increased

When a piece of metal weighing 200 g was heated from 20 to 60 degrees, its internal energy increased by 2400 J. Find the heat capacity of the metal.

Initial data: m (mass of a piece of metal) = 200 g (0.2 kg); t1 (initial temperature of a piece of metal) = 20 ºС; t2 (final temperature) = 60 ºС; Q (increase in the internal energy of a piece of metal) = 2400 J.

We express the specific heat of the metal from the formula: Q = C * m * (t2 – t1), whence C = Q / (m * (t2 – t1)).

Calculation: C = 2400 / (0.2 * (60 – 20)) = 2400/8 = 300 J / (kg * ºС).

Answer: The heat capacity of the metal is 300 J / (kg * ºС).