When a piece of tin with a mass of 100 g was cooled to a temperature of 33 s
| February 11, 2021 | education
When a piece of tin with a mass of 100 g was cooled to a temperature of 33 s, 5 kJ of energy was released. Determine the temperature of the tin before cooling.
We find the temperature of a piece of tin before cooling from the formula:
Q = C * m * (t2 – t1), where Q is the energy released during cooling of a piece of tin (Q = 5 kJ or 5000 J) C is the specific heat capacity of tin (according to the table C = 230 J / (K * kg)), m – mass of a piece of tin (m = 100 g or 0.1 kg), t2 – temperature before cooling, t1 – temperature after cooling (t2 = 33 ºС).
t2 – t1 = Q / (C * m) and t2 = Q / (C * m) + t1.
t2 = 5000 / (230 * 0.1) + 33 = 250 ºС.
Answer: The temperature of a piece of tin before cooling was 250 ºС.
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