When a steel plate weighing 400 g is heated with an alcohol lamp, alcohol with a mass of 2 g

| April 26, 2021 | education

When a steel plate weighing 400 g is heated with an alcohol lamp, alcohol with a mass of 2 g burns out. How much has the temperature of the plate changed?

mpl = 400 g = 0.4 kg.

msp = 2 g = 0.002 kg.

qsp = 28 MJ / kg = 28 * 10 ^ 6 J.

C = 500 J / kg * ° C.

Δt -?

The amount of heat Qsp, which is released during the combustion of alcohol, is used to heat the steel plate Qpl: Qsp = Qpl.

The amount of heat Qsp, which is released during the combustion of alcohol, is determined by the formula: Qsp = qsp * msp, where qsp is the specific heat of combustion of alcohol, msp is the mass of alcohol that burned.

The amount of heat Qpl, which is necessary for heating the plate, is determined by the formula: Qpl = C * mpl * Δt, where C is the specific heat capacity of steel, mpl is the mass of the plate, and Δt is the change in the temperature of the plate.

qsp * msp = C * mpl * Δt.

Δt = qsp * msp / C * mpl.

Δt = 28 * 10 ^ 6 J * 0.002 kg / 500 J / kg * ° C * 0.4 kg = 280 ° C.

Answer: The temperature of the plate will increase by Δt = 280 ° C.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.