When a steel plate with a mass of 400 g is heated with an alcohol lamp

| July 17, 2021 | education

When a steel plate with a mass of 400 g is heated with an alcohol lamp, alcohol with a mass of 2 g burns out. How much has the temperature of the plate changed?

The amount of heat that will be released during the combustion of alcohol:
Q = q * mс, where q is the specific heat of combustion of alcohol (q = 28 MJ = 28 * 10 ^ 6 J / kg), mс is the mass of alcohol (mс = 2 g = 2 * 10 ^ -3 kg).
Required heat for heating:
Q = C * mp * ∆t, where C is the specific heat capacity of steel (C = 500J / (kg * K)), mw is the mass of the plate (mp = 400 g = 0.4 kg), ∆t is the change in the plate temperature ( ºС).
q * mc = C * mp * ∆t;
∆t = q * mc / (C * mp) = (28 * 10 ^ 6) * (2 * 10 ^ -3) / (500 * 0.4) = 280 ºС.
Answer: The temperature of the plate has changed by 280 ºС.



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