When acetic acid interacts with aluminum, 2.24 L of hydrogen was released.

When acetic acid interacts with aluminum, 2.24 L of hydrogen was released. How to find the mass of acetic acid that has reacted?

Metallic aluminum interacts with acetic acid. In this case, aluminum acetate is formed and elemental hydrogen is released. The interaction is described by the following chemical equation.

Al + 3CH3COOH = Al (CH3COO) 3 + 3/2 H2;

Let’s find the chemical amount of the evolved gaseous hydrogen.

To do this, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 2.24 / 22.4 = 0.1 mol;

To obtain such an amount of hydrogen, it is required that 0.1 x 2 = 0.2 mol of acid has reacted.

Let’s calculate its mass.

M CH3COOH = 12 + 3 + 12 + 16 x 2 + 1 = 60 grams / mol;

m CH3COOH = 0.2 x 60 = 12 grams;