When Al (OH) 3 interacts with HCl, 5 mol of AlCl3 is formed. What mass of al (oh) 3 is required for this?

1. Let’s compose the equation of the reaction of interaction of aluminum hydroxide with hydrochloric acid:

Al (OH) 3 + 3HCl = AlCl3 + 3H2O;

2. Let’s calculate the molecular weight of aluminum hydroxide:

27 + 16 * 3 + 1 * 3 = 78 g / mol;

3. Aluminum hydroxide is preceded by the same coefficient as aluminum chloride. This means that the amount of substance in the hydroxide is 5 mol. Let’s find the mass of aluminum hydroxide:

78 * 5 = 390 grams;

Answer: You need 390 grams of aluminum hydroxide.

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