When aluminum interacts with a 20% solution of copper (II) chloride weighing 150 g, copper

| March 25, 2021 | education

When aluminum interacts with a 20% solution of copper (II) chloride weighing 150 g, copper and aluminum chloride were obtained. What is the mass of the resulting copper? Reaction scheme: Al + CuCl₂ → Cu + AlCl₃

1.Let’s find the mass of CuCl2 in the solution.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (150 g × 20%): 100% = 30g.

2.Let’s find the amount of substance CuCl2:

M (CuCl2) = 135g / mol.

n = 30 g: 135 g / mol = 0.22 mol.

Let’s find the quantitative ratios of substances.

2Al + 3CuCl₂ → 3Cu + 2AlCl₃

For 3 mol of CuCl2, there are 3 mol of Cu.

Substances are in quantitative ratios 1: 1.

The amount of substance Cu and CuCl₂ are equal.

n (CuCl₂) = n (Cu) = 0.22 mol.

Let us find the mass of Cu.

M (Cu) = 64 g / mol.

m = n × M.

m = 64 g / mol × 0.22 mol = 14.08 g.

Answer: 14.08 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.