When aluminum was obtained by electrolysis of an Al2O3 solution in a molten substance, a current of 20 kA

| March 15, 2021 | education

When aluminum was obtained by electrolysis of an Al2O3 solution in a molten substance, a current of 20 kA passed at a voltage on the electrodes of 5 V. Find the time during which 1 ton of aluminum will be released. What work was done with the electric current? Electrochemical equivalent of aluminum 0.093 mg / C

Data: I (current during electrolysis) = 20 kA (20 * 10 ^ 3 A); U (voltage across the electrodes) = 5 V; m (required mass of aluminum) = 1 t (in SI m = 1000 kg).

Constants: according to the condition k (electrochemical equivalent of aluminum) = 0.093 mg / kg (in SI k = 9.3 * 10 ^ -8 kg / C).

1) The duration of electrolysis (Faraday’s first law): m = k * I * t, whence t = m / (I * k) = 1000 / (20 * 10 ^ 3 * 9.3 * 10 ^ -8) = 537634, 8 p.

2) The work of the current (Joule-Lenz law): A = U * I * t = 5 * 20 * 10 ^ 3 * 537634.8 ≈ 53.76 * 10 ^ 9 J (53.76 GJ).



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