When an excess of hydrochloric acid acts on calcium carbonate with a mass of 25 g.

When an excess of hydrochloric acid acts on calcium carbonate with a mass of 25 g. obtained carbon monoxide 4 weighing 10 g. Determine the product yield.

Let us determine the theoretically possible mass of carbon monoxide that can be obtained under these conditions.

The reaction of calcium carbonate with hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

One mole of limestone produces one carbon monoxide.

Let’s find the amount of limestone substance.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of substance will be:

N CaCO3 = 25/100 = 0.25 mol;

Let’s find the theoretical mass of carbon dioxide.

Its molar mass is:

M CO2 = 12 + 16 x 2 = 44 grams / mol;

The mass of the substance will be:

m CO2 = 0.25 x 44 = 11 grams;

The reaction yield will be:

K = 10/11 = 0.909 = 90.9%