When approaching the station, the driver turned off the electric train’s engine, after which the train began to move with a constant acceleration of 0.1 m / s2. What is the length of the train’s movement to stop, if at the moment the engine was turned off, its speed was 54 km / h? How long did the train stop?
Data: a (constant acceleration of the train) = 0.1 m / s2; V0 (speed of the considered electric train at the moment of engine shutdown) = 54 km / h (in SI V0 = 15 m / s).
1) Determine the length of movement: S = (V0 ^ 2 – V ^ 2) / 2a = (15 ^ 2 – 0 ^ 2) / (2 * 0.1) = 1125 m.
2) Calculate the braking duration of the considered electric train with the composition: t = (V0 – V) / a = (15 – 0) / 0.1 = 150 s.
Answer: The deceleration of the considered electric train lasted 150 s; during this time he passed 1125 m.
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