When approaching the station, the driver turned off the electric train’s engine, after which the train began

When approaching the station, the driver turned off the electric train’s engine, after which the train began to move with a constant acceleration of 0.1 m / s2. What is the length of the train’s movement to stop, if at the moment the engine was turned off, its speed was 54 km / h? How long did the train stop?

Data: a (constant acceleration of the train) = 0.1 m / s2; V0 (speed of the considered electric train at the moment of engine shutdown) = 54 km / h (in SI V0 = 15 m / s).

1) Determine the length of movement: S = (V0 ^ 2 – V ^ 2) / 2a = (15 ^ 2 – 0 ^ 2) / (2 * 0.1) = 1125 m.

2) Calculate the braking duration of the considered electric train with the composition: t = (V0 – V) / a = (15 – 0) / 0.1 = 150 s.

Answer: The deceleration of the considered electric train lasted 150 s; during this time he passed 1125 m.