When approaching the station, the speed of the train within 25 seconds decreased

When approaching the station, the speed of the train within 25 seconds decreased from 90 km / h to 45 km / h. Find the train acceleration module.

Given
v0 = 90 km / h
v = 45 km / h
t = 25 sec
Find: a
SI
90 km / h = 90 x 1000m: 3600 sec = 25 m / s
45 km / i = 12.5 m / s
Decision
a = (v – v0) / t
a = (25 – 12.5 m / s) / 25 sec = 0.5 m / s ^ 2
Answer: a = 0.5 m / s ^ 2



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