When benzene was exposed to concentrated nitric acid weighing 200 g with a mass fraction of acid of 63%

| April 1, 2021 | education

When benzene was exposed to concentrated nitric acid weighing 200 g with a mass fraction of acid of 63%, nitrobenzene was formed. Determine the mass of nitrobenzene obtained if the mass fraction of the product yield is 94%.

First, we write down the equation of reactions.
C6H6 + HNO3 = C6H5NO2 + H2O.
We find the mass of nitric acid.
W = mr.w / mr-ra × 100%.
m.w = 200 × 63/100 = 125 g.
Next, we find the amount of nitric acid substance.
n (HNO3) = 125 g / 63 g / mol = 1.98 mol.
Find the amount of nitrobenzene substance.
1.98 mol HNO3 – x mol С6Н5NO2.
1 mol HNO3 – 1 mol C6H5NO2.
n (C6H5NO2) = 1.98 × 1 ÷ 1 = 1.98 mol C6H5NO2.
m (C6H5NO2) theor. = 123 × 1.98 = 246 g.
Next, we find a practical mass.
m (C6H5NO2) = 246 × 0.94 = 213.24 g.
Answer: m (C6H5NO2) = 213.24 g.



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