When boiling water, 690 kJ of energy was expended. Find the mass of evaporated water.
| November 27, 2020 | education
Given:
Q = 690 kJ = 690000 J
L = 2256 kJ / kg = 2256000 J
Find: m -? kg
Decision :
L – Specific heat of vaporization.
Q = L * m – the amount of heat released as a result of vaporization.
m = Q / L.
[L] = J / kg.
m = 690000/2256000 = 690000/2256000 = 0.30585 = 0.306 (kg).
Answer: 0.306 kg or 306 grams.
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