When boiling water, 690 kJ of energy was expended. Find the mass of evaporated water.

Given:
Q = 690 kJ
From the reference material, we learned that the specific heat of self-formation for water is
r = 2 260 kJ / kg
Find: m -?
SI:
Q = 690,000 J
r = 2,260,000 J / kg
Decision:
Q = mr
m = Q / r = 690,000 / 2,260,000 ≈ 0.305 kg
Answer: 0.305 kg



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