When burning 12.8 copper, copper oxide is formed.

Most likely, you need to find the mass of the formed oxide:
2Cu + O2 = 2CuO
n (Cu) = m \ M = 12.8 \ 64 = 0.2 mol
for ur-th p-and n (Cu) = n (CuO) = 0.2 mol
m (CuO) = nM = 0.2 * 80 = 16 g
Answer: 16 g



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