When burning 3 mol of silicon, 160 g of silicon oxide was obtained. Find the mass fraction of the reaction product yield.

given:
n (Si) = 3 mol
m (SiO2) = 160 g
to find:
V (output) (SiO2)
decision:
Si + O2 → SiO2
n (Si): n (SiO2) = 1: 1 = 3 mol
m (SiO2) = n * M = 3 mol * 48 g / mol = 144 g
V (SiO2) = m theoretical: m practical = 144 g: 160 g = 0.9 * 100% = 90%
answer: 90%



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