When burning 32g coal, oxygen oxide gas is obtained, under normal conditions

When burning 32g coal, oxygen oxide gas is obtained, under normal conditions, determine the amount of carbon monoxide.

m (C) = 32 g.

Let us determine the amount of carbon monoxide formed under normal conditions. First, we write down the equation of reactions.

C + O2 = CO2

First, we calculate the molar mass of carbon and carbon monoxide. We write down the solution.

M (C) = 12 g / mol

M (CO2) = 12 + 16 * 2 = 44 g / mol

Further, according to the reaction equation, we find the mass of carbon dioxide.

32 g carbon – x g carbon monoxide

12 g / mol С – 44 g / mol СО2

X = 32 * 44: 12 = 117 gCO2

Find the amount of carbon monoxide substance.

n = m / M

n (CO2) = 117 g / 44 g / mol = 2.7 mol.

Answer: n = 2.7 mol.



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