When calcining limestone (CaCo3), quicklime (CaO) and carbon dioxide are obtained.

When calcining limestone (CaCo3), quicklime (CaO) and carbon dioxide are obtained. Calculate the mass of quicklime that can be obtained from calcium carbonate CaCO3 and weighing 100 kg.

The decomposition reaction of limestone (calcium carbonate) is described by the following equation:

CaCO3 = CaO + CO2;

In the course of the reaction, 1 molecule of calcium oxide and 1 molecule of carbon dioxide are synthesized from 1 molecule of calcium carbonate.

Let’s calculate the amount of substance contained in 100 kg of chalk.

To do this, divide the available weight of chalk by the weight of 1 mole of chalk.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 100,000 / 100 = 1,000 mol;

The same amount of calcium oxide will be synthesized. Let’s calculate its weight.

To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.

M CaO = 40 +16 = 56 grams / mol;

m CaO = 1000 x 56 = 56 000 grams = 56 kg.



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