When calcium interacts with water, 11.2 liters of hydrogen were released. Calculate how many grams of calcium it took.

Given:
V (H2) = 11.2 L
Ca + H2O
Find: m (Ca)
Decision:
1.Ca + 2 H20-> Ca (OH) 2 + H2
2.n (H2) = V / Vm = 11.2 l / 22.4 l / mol = 0.5 mol
3. We make the proportion x / 1 = 0.5 / 1 x = 0.5 mol (n (Ca))
4.m (Ca) = nM = 0.5 mol * 40 g / mol = 20 g M (Ca) = 40 g / mol
Answer: 20 g



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