When calcium oxide interacts with water, 0.7 mol of calcium hydroxide is formed. Calculate the mass of the calcium hydroxide obtained.

Given:
n (Ca (OH) 2) = 0.7 mol
To find:
m (Ca (OH) 2)
Decision:
CaO + H2O = Ca (OH) 2
m (Ca (OH) 2) = n * M = 0.7 mol * 74 g / mol = 51.8 g
Answer: 51.8 g



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