When carbon monoxide (IV) was passed through a solution of barium hydroxide with

When carbon monoxide (IV) was passed through a solution of barium hydroxide with a mass fraction of 16%, a precipitate weighing 59.1 grams was formed. Calculate the mass of the initial barium hydroxide solution.

Let’s calculate the chemical amount of synthesized barium carbonate.

To do this, we divide its weight by its molar mass, equal to the sum of the molar weights of the atoms included in the molecule.

M BaCO3 = 137 + 12 + 16 x 3 = 197 grams / mol;

N BaCO3 = 59.1 / 197 = 0.3 mol;

To obtain such an amount of insoluble precipitate, it is necessary to take the same amount of barium chloride. Let’s calculate its weight. For this purpose, we multiply its chemical amount by its molar mass.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol;

m BaCl2 = 0.3 x 208 = 62.4 grams;

The weight of a 16% solution of this salt containing 62.4 grams of salt will be equal to 62.4 / 0.16 = 390 grams;