When cesium and chlorine interact, a salt is obtained. Find the mass of cesium and chlorine

When cesium and chlorine interact, a salt is obtained. Find the mass of cesium and chlorine if the amount of the substance of the resulting salt is = 2 mol.

Given:
n (salt) = 2 mol

To find:
m (Cs) -?
m (Cl2) -?

1) Write the reaction equation:
2Cs + Cl2 => 2CsCl;
2) Determine the amount of substance Cs (taking into account the coefficients in the reaction equation):
n (Cs) = n (CsCl) = 2 mol;
3) Calculate the mass of Cs:
m (Cs) = n (Cs) * M (Cs) = 2 * 133 = 266 g;
4) Determine the amount of substance Cl2 (taking into account the coefficients in the reaction equation):
n (Cl2) = n (CsCl) / 2 = 2/2 = 1 mol;
5) Calculate the mass of Cl2:
m (Cl2) = n (Cl2) * M (Cl2) = 1 * 71 = 71 g.

Answer: The mass of Cs is 266 g; Cl2 – 71 g.