When cooling a steel part with a mass of 5 kg, an amount of heat of 25 kJ was released.

When cooling a steel part with a mass of 5 kg, an amount of heat of 25 kJ was released. How many degrees has the part temperature changed? Specific heat capacity of steel 500 J / (kg • s)

To calculate the change in temperature of a given steel part, apply the formula: Q = Cc * m * Δt and Δt = Q / (Cc * m).

Values of variables and constants: Q is the heat emitted by the part (Q = 25 kJ = 25 * 10 ^ 3 J); Cc – specific heat capacity of steel (according to the condition Cc = 500 J / (kg * K)); m is the mass of the part (m = 5 kg).

Let’s make a calculation: Δt = 25 * 10 ^ 3 / (500 * 5) = 10 ºС.

Answer: The temperature of the given part has dropped by 10 ºС.