When copper chloride 2 interacts with 51 g of aluminum, copper was released. calculate its mass.

univerkov | January 17, 2021 | education

Given:
m (Al) = 51 g
Find: m (Cu)
Decision:
3CuCl2 + 2Al = 2AlCl3 + 3Cu
n (Al) = m / M = 51 g / 27 g / mol = 1.88 mol
n (Al): n (Cu) = 2: 3
n (Cu) = 1.88 mol / 2 * 3 = 2.82 mol
m (Cu) = n * M = 2.82 mol * 64 g / mol = 180.48 g
Answer: 180.48 g

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.