When copper interacts with concentrated sulfuric acid, sulfur oxide (IV) is released, how much copper must react to obtain 3.2 g of SO2.
Let’s find the amount of sulfur oxide SO2 by the formula:
n = m: M.
M (SO2) = 32 + 32 = 64 g / mol.
n = 3.2 g: 64 g / mol = 0.05 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O.
According to the reaction equation, there is 1 mole of copper per 2 mol of sulfur oxide. The substances are in quantitative ratios of 1: 1.
The amount of copper and sulfur oxide will be equal.
n (SO2) = n (Cu) = 0.05 mol.
Let’s find the mass of copper.
m = n M.
M (Cu) = 64 g / mol.
m = 0.05 mol × 64 g / mol = 3.2 g.
Answer: m = 3.2 g.
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