When copper interacts with concentrated sulfuric acid, sulfur oxide (IV) is released

When copper interacts with concentrated sulfuric acid, sulfur oxide (IV) is released, how much copper must react to obtain 3.2 g of SO2.

Let’s find the amount of sulfur oxide SO2 by the formula:

n = m: M.

M (SO2) = 32 + 32 = 64 g / mol.

n = 3.2 g: 64 g / mol = 0.05 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O.

According to the reaction equation, there is 1 mole of copper per 2 mol of sulfur oxide. The substances are in quantitative ratios of 1: 1.

The amount of copper and sulfur oxide will be equal.

n (SO2) = n (Cu) = 0.05 mol.

Let’s find the mass of copper.

m = n M.

M (Cu) = 64 g / mol.

m = 0.05 mol × 64 g / mol = 3.2 g.

Answer: m = 3.2 g.

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