When copper with a mass of 12.8 g interacted with oxygen, a CuO compound with a mass of 16.0 g was formed.

When copper with a mass of 12.8 g interacted with oxygen, a CuO compound with a mass of 16.0 g was formed. Make an equation for the ongoing chemical reaction. Determine the mass of oxygen that has reacted.

Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:

Cu + ½ O2 = CuO ↑;

Let’s calculate the chemical amount of copper. For this purpose, we divide the mass of the available substance by the weight of 1 mole.

M Cu = 64 grams / mol;

N Cu = 12.8 / 64 = 0.2 mol;

The same amount of copper oxide can be obtained.

Determine the weight of copper oxide. To do this, multiply the amount of substance by the weight of 1 mole.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 0.2 x 80 = 16 grams;