When decomposing 16.8 g of sodium bicarbonate, carbon dioxide is released in volume …

Let’s execute the solution:
1. By the condition of the problem, we write down the equation:
m = 16.8 g. X l -?
2NaHCO3 = CO2 + Na2CO3 + H2O – decomposition, carbon dioxide is released;
2. Let’s make the calculations:
M (NaHCO3) = 83.9 g / mol;
M (CO2) = 44 g / mol;
Y (NaHCO3) = m / M = 16.8 / 83.9 = 0.2 mol.
3. Proportion:
0.2 mol (NaHCO3) – X mol (CO2);
– 2 mol – 1 mol from here, X mol (CO2) = 0.2 * 1/2 = 0.1 mol.
4. Find the volume of the product:
V (CO2) = 0.1 * 22.4 = 2.24 liters.
Answer: carbon monoxide was obtained with a volume of 2.24 liters.