When ethanol with a mass of 13.8 g interacted with copper (II) oxide with a mass of 28 g, an aldehyde was

| July 9, 2021 | education

When ethanol with a mass of 13.8 g interacted with copper (II) oxide with a mass of 28 g, an aldehyde was obtained, the mass of which was 9.24 g. Calculate the yield of the reaction product.

1. The interaction of ethanol with copper oxide proceeds according to the equation:

C2H5OH + CuO → CH3CHO + Cu + H2O;

2.Calculate the chemical amounts of reactants:

n (C2H5OH) = m (C2H5OH): M (C2H5OH);

M (C2H5OH) = 2 * 12 + 5 + 17 = 46 g / mol;

n (C2H5OH) = 13.8: 46 = 0.3 mol;

n (CuO) = m (CuO): M (CuO);

M (CuO) = 64 + 16 = 80 g / mol;

n (CuO) = 28: 80 = 0.35 mol;

3.The lack of alcohol is taken, therefore, the theoretical amount of aldehyde:

ntheor (CH3CHO) = n (C2H5OH) = 0.3 mol;

4.Let’s find the theoretical mass of the resulting acetaldehyde:

mtheor (CH3CHO) = ntheor (CH3CHO) * M (CH3CHO);

M (CH3CHO) = 12 + 3 + 12 + 17 = 44 g / mol;

mtheor (CH3CHO) = 0.3 * 44 = 13.2 g;

5. calculate the yield of the reaction product:

ν = mpract (CH3CHO): mtheor (CH3CHO) = 9.24: 13.2 = 0.7 or 70%.

Answer: 70%.



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