When ethanol with a mass of 9.2 g interacts with oxide copper (II) oxide, a mass of 7.04

| January 18, 2021 | education

When ethanol with a mass of 9.2 g interacts with oxide copper (II) oxide, a mass of 7.04 g was obtained. Determine the practical yield (%) of the organic reaction product.

To solve the problem, write the equation:
1. С2Н5ОН + CuO = CH3 – COH + Cu + H2O – alcohol oxidation with copper oxide occurs when heated, acetaldehyde is released;
2. Let’s make the calculations:
M (C2H5OH) = 46 g / mol;
M (C2H4O) = 44 g / mol.
3. Determine the amount of mol of alcohol, aldehyde:
Y (C2H5OH) = m / M = 9.2 / 46 = 0.2 mol;
Y (C2H4O) = 0.2 mol since the amount of these substances according to the equation is 1 mol.
4. Find the theoretical mass of ethanal by the formula:
m (C2H4O) = Y * M = 0.2 * 44 = 8.8 g.
5. We calculate the product yield as follows:
W = m (practical) / m (theoretical) * 100;
W = 7.04 / 8.8 * 100 = 80%.
Answer: The practical yield of acetaldehyde is 80%.



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