When ethylene was passed through bromine water, the mass of its solution increased by 5.6 g. What mass of dibromoethane (g) is formed as a result of the reaction?
C2H4 + Br2 = C2H4Br2
The increase in the mass of the solution corresponds to the mass of the reacted ethylene. Let’s find the amount of ethylene substance:
n (C2H4) = m (C2H4) / M (C2H4) = 5.6 / 28 = 0.2 mol;
According to the stoichiometry of the reaction:
n (C2H4Br2) = n (C2H4) = 0.2 mol;
Let’s find the mass of dibromoethane:
m (C2H4Br2) = n (C2H4Br2) * M (C2H4Br2) = 0.2 * 188 = 37.6 g.
Answer: m (C2H4Br2) = 37.6 g.
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