When ethylene was passed through bromine water, the mass of its solution increased by 5.6 g

When ethylene was passed through bromine water, the mass of its solution increased by 5.6 g. What mass of dibromoethane (g) is formed as a result of the reaction?

C2H4 + Br2 = C2H4Br2

The increase in the mass of the solution corresponds to the mass of the reacted ethylene. Let’s find the amount of ethylene substance:

n (C2H4) = m (C2H4) / M (C2H4) = 5.6 / 28 = 0.2 mol;

According to the stoichiometry of the reaction:

n (C2H4Br2) = n (C2H4) = 0.2 mol;

Let’s find the mass of dibromoethane:

m (C2H4Br2) = n (C2H4Br2) * M (C2H4Br2) = 0.2 * 188 = 37.6 g.

Answer: m (C2H4Br2) = 37.6 g.