When ethylene was passed through bromine water, the mass of the bottle with bromine increased by 14 g. Determine the volume of ethylene reacted and the mass of dibromoethane formed.
C2H4 + Br2 = C2H4Br2
n (C2H4) = m: M = 14: 28 = 0.5 mol
V (C2H4) = n * Vn = 0.5 * 22.4 = 11.2 l
n (C2H4Br2) = n (C2H4) = 0.5 mol
m (C2H4Br2) = n x M = 0.5 x 188 = 94 g
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