When expanding the gas at a constant pressure of 160 kPa, a work of 320 kJ was performed.

When expanding the gas at a constant pressure of 160 kPa, a work of 320 kJ was performed. What will be the volume of gas if its initial volume was 12 dm3.

Initial data: P (constant gas pressure) = 160 kPa (160 * 10 ^ 3 Pa); A (work that was done during gas expansion) = 320 kJ (320 * 10 ^ 3 J); V1 (initial gas volume) = 12 dm3 (12 * 10 ^ -3 m3).

The steady-state gas volume is determined from the formula: A = P * ΔV = P * (V2 – V1), whence V2 = A / P + V1.

Calculation: V2 = 320 * 10 ^ 3 / (160 * 10 ^ 3) + 12 * 10 ^ -3 = 2 + 12 * 10 ^ -3 = 2.012 m3.

Answer: The volume of gas after isobaric expansion will be equal to 2.012 m3.