When fired from a spring pistol vertically upwards, the spring with a stiffness of 1000N / m

When fired from a spring pistol vertically upwards, the spring with a stiffness of 1000N / m was compressed by 2 cm, to what height the ball with a mass of 100 g rises.

To determine the maximum lifting height of the ball after the shot, we apply the law of conservation of energy: m * g * h = 0.5 * k * Δx ^ 2, whence h = 0.5 * k * Δx ^ 2 / (m * g).

Values of variables: k – spring stiffness (k = 1000 N / m); Δx – compression of the spring (Δx = 2 cm; in SI Δx = 0.02 m); m is the mass of the ball (m = 100 g; in SI m = 0.1 kg); g – acceleration due to gravity (g ≈ 10 m / s2).

Let’s perform the calculation: h = 0.5 * 1000 * 0.02 ^ 2 / (0.1 * 10) = 0.2 m.

Answer: After firing the ball will rise to a height of 0.2 m.