When firing barium carbonate with a mass of 300 g with a mass fraction of impurities of 15%

| September 10, 2021 | education

When firing barium carbonate with a mass of 300 g with a mass fraction of impurities of 15%, carbon dioxide is released with a mass

Barium carbonate roasting takes place at a temperature of 1400: BaCO3 = BaO + CO2.
1) Find the mass of impurities in barium carbonate. To do this, we multiply the mass fraction of impurities by the mass of carbonate and divide by one hundred percent: 300 * 15/100 = 45g.
2) Find the mass of pure carbonate substance: 300 – 45 = 255g.
3) Molar mass of barium carbonate: 137 + 12 + 48 = 197.
4) The amount of barium carbonate substance: 255/197 = 1.3 mol.
5) The amount of carbon dioxide substance is equal to the amount of barium carbonate substance and is equal to 1.3 mol.
6) Molar mass of gas: 12 + 32 = 44.
7) Mass of carbon dioxide: 44 * 1.3 = 57.2g



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